(2x^2+2x+6)=(3x+5)

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Solution for (2x^2+2x+6)=(3x+5) equation: 



(2x^2+2x+6)=(3x+5)

We move all terms to the left:

(2x^2+2x+6)-((3x+5))=0

We get rid of parentheses

2x^2+2x-((3x+5))+6=0



We calculate terms in parentheses: -((3x+5)), so:

(3x+5)

We get rid of parentheses

3x+5

Back to the equation:

-(3x+5)



We get rid of parentheses

2x^2+2x-3x-5+6=0

We add all the numbers together, and all the variables

2x^2-1x+1=0

a = 2; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·2·1
Δ = -7
Delta is less than zero, so there is no solution for the equation

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